BBYET-143 · June 2025 · English

IGNOU BBYET-143 June 2025 Previous Year Question Paper

Economic Botany And Biotechnology

Structured previous year question paper for BBYET-143, June 2025 session.

Max marks: 50 · Questions: 8

Verified: 29 Jul 2026

BACHELOR OF SCIENCE

(UGC) (CBCS) (B. SC.)

Term-End Examination

June, 2025

BBYET-143 : ECONOMIC BOTANY AND

BIOTECHNOLOGY

Time : 2 Hours Maximum Marks : 50

Note : Question No. 1 is compulsory. Marks are

indicated against each = question.

Attempt any four questions from

Question Nos. 2 to 7.

Q1.(a) Write botanical names of the following plants : 5x1=5 @) Soybean

(1) Pigeon pea Gii) Turmeric

(iv) Groundnut

(v) Green Gram

(b) Fillin the blanks : 5x1=5

(6) The Hungarian engineer coined the term ‘biotechnology’.

(i) The cell receiving recombinant DNA tagged with will give green fluorescence in reporter gene assay.

(iii) is the most preferred external source of carbon used in the plant tissue culture media.

(iv) The heat-stable Taq DNA polymerase enzyme is isolated from the bacterium

(v) The part of Tumor inducing (Ti) plasmid transferred to a plant genome during Agrobacterium- mediated transformation is termed

Q2.Discuss the significance and loss of genetic diversity.

Q3.(a) Define the term ‘totipotency’ and list its various applications. 5

(b) What are synthetic seeds ? List several advantages of the same.

Q4.Explain the process of development of insect resistant transgenic plant giving suitable example.

Q5.Write the botanical name of castor plant.

Q6.Describe the morphology of the plant, method of cultivation and uses of castor plant.

Q7.What are secondary metabolites ? List the advantages of plant tissue culture in increasing the production of these compounds. Name any four such metabolites produced commercially using plant tissue culture.

Q8.Write short notes on any four of the following : 4x22=10

(a) Health benefits of curcumin

(b) Micropropagation

(c) Marker assisted breeding

(d) Enzyme-linked immunosorbent assay (ELISA)

(e) Western blotting 5x1=5 4x2°=

(10)